INDIAN WELLS — Two-time Wimbledon champion Petra Kvitova was eliminated from the
WTA 1000 event at Indian Wells on Thursday (IST), losing 4-6, 6-3, 6-4 to
France's Varvara Gracheva in the first round.
World No. 70 Gracheva won 68 percent of points on her first
serve and 56 percent on her second to take the match in two hours and 22
minutes against the 34-year-old Czech.
Kvitova, who gave birth to son Petr last July, returned from
an 18-month maternity leave last week in Austin, where she lost 3-6, 6-4, 6-4
to Jodie Burrage in the first round.
Kvitova, who won Wimbledon in 2011 and 2014, is still
searching for her first victory since returning from a hiatus.
"I really want to congratulate her," Gracheva said
in an on-court interview. "She had a child quite recently and I'm so happy
that she now has the role of a mother and a tennis player, which is very
demanding. It's very inspiring for sports, athletes, women - it's just amazing.
Petra, my admiration to you. You're the best."
Kvitova, 34, struggled for rhythm against her Russian-born
opponent, committing a series of uncharacteristic unforced errors, including
eight double faults, reports Xinhua.
Gracheva will meet Russian ninth seed Mirra Andreeva in the
next round with a place in the last 32 at stake. Andreeva, 17, defeated three
Grand Slam winners en route to becoming the youngest ever WTA 1000 champion in
Dubai last month.
In other action early on Day 1, France’s Caroline Garcia
defeated American Bernarda Pera 6-3, 6-4, while New Zealand’s Lulu Sun toppled
Slovakia’s Rebecca Sramkova 6-3, 1-6, 7-6(2).
Italy’s Elisabetta Cocciaretto went through when Mexico’s
Renata Zarazua was forced to retire, trailing 6-4, 1-0.